1、极验滑动验证码原理0 y, a$ m% _. O" d% |
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以上图片是最典型的要属于极验滑动认证了，极验官网：http://www.geetest.com/。
9 }2 a. i% M( W% w, W现在极验验证码已经更新到了 3.0 版本，截至 2017 年 7 月全球已有十六万家企业正在使用极验，每天服务响应超过四亿次，广泛应用于直播视频、金融服务、电子商务、游戏娱乐、政府企业等各大类型网站
0 ^/ ?/ r* N! K* Z& B对于这类验证，如果我们直接模拟表单请求，繁琐的认证参数与认证流程会让你蛋碎一地，我们可以用selenium驱动浏览器来解决这个问题，大致分为以下几个步骤：3 j4 z) i9 t( a+ L9 k) f
1、输入用户名，密码
! \# e- I$ u" k* T: ]' G2、点击按钮验证，弹出没有缺口的图
$ a1 i3 S1 v% v. [' T& \4 d3、获得没有缺口的图片7 P6 S2 w- O% {$ Y* U& @3 b" W
4、点击滑动按钮，弹出有缺口的图1 o a b2 C; ~8 D( x
5、获得有缺口的图片
& \( ]/ ]4 s% t/ D2 Y6、对比两张图片，找出缺口，即滑动的位移
- Y$ X8 M: z' P. N! e7、按照人的行为行为习惯，把总位移切成一段段小的位移2 k r" ?) }8 v a& U3 o, o7 e
8、按照位移移动
; o! n4 r) H! `8 S9、完成登录
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) _8 s; K. V9 `! @0 Y2、位移移动需要的基础知识2 c. i4 d% J- n9 R: V
位移移动相当于匀变速直线运动，类似于小汽车从起点开始运行到终点的过程（首先为匀加速，然后再匀减速）。 V: X9 {8 v2 p8 s! Q
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其中a为加速度，且为恒量（即单位时间内的加速度是不变的），t为时间8 I4 O/ X3 L# q5 [6 q5 r, X0 N
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& }+ r$ U; x- X# M; |: L* x位移移动的代码实现; ?; G8 o$ g, m, }- q2 l
def get_track(distance):
'''
拿到移动轨迹，模仿人的滑动行为，先匀加速后匀减速
匀变速运动基本公式：
①v=v0+at
②s=v0t+(1/2)at²
③v²-v0²=2as
:param distance: 需要移动的距离
:return: 存放每0.2秒移动的距离
'''
# 初速度
v=0
# 单位时间为0.2s来统计轨迹，轨迹即0.2内的位移
t=0.1
# 位移/轨迹列表，列表内的一个元素代表0.2s的位移
tracks=[]
# 当前的位移
current=0
# 到达mid值开始减速
mid=distance * 4/5
distance += 10 # 先滑过一点，最后再反着滑动回来
while current < distance:
if current < mid:
# 加速度越小，单位时间的位移越小,模拟的轨迹就越多越详细
a = 2 # 加速运动
else:
a = -3 # 减速运动
# 初速度
v0 = v
# 0.2秒时间内的位移
s = v0*t+0.5*a*(t**2)
# 当前的位置
current += s
# 添加到轨迹列表
tracks.append(round(s))
# 速度已经达到v,该速度作为下次的初速度
v= v0+a*t
# 反着滑动到大概准确位置
for i in range(3):
tracks.append(-2)
for i in range(4):
tracks.append(-1)
return tracks
对比两张图片，找出缺口& C/ v( n$ z7 V
def get_distance(image1,image2):
'''
拿到滑动验证码需要移动的距离
:param image1:没有缺口的图片对象
:param image2:带缺口的图片对象
:return:需要移动的距离
'''
# print('size', image1.size)
threshold = 50
for i in range(0,image1.size[0]): # 260
for j in range(0,image1.size[1]): # 160
pixel1 = image1.getpixel((i,j))
pixel2 = image2.getpixel((i,j))
res_R = abs(pixel1[0]-pixel2[0]) # 计算RGB差
res_G = abs(pixel1[1] - pixel2[1]) # 计算RGB差
res_B = abs(pixel1[2] - pixel2[2]) # 计算RGB差
if res_R > threshold and res_G > threshold and res_B > threshold:
return i # 需要移动的距离
获得图片
# ?! D# X# T3 Z* o! Ldef merge_image(image_file,location_list):
"""
拼接图片
:param image_file:
:param location_list:
:return:
"""
im = Image.open(image_file)
im.save('code.jpg')
new_im = Image.new('RGB',(260,116))
# 把无序的图片 切成52张小图片
im_list_upper = []
im_list_down = []
# print(location_list)
for location in location_list:
# print(location['y'])
if location['y'] == -58: # 上半边
im_list_upper.append(im.crop((abs(location['x']),58,abs(location['x'])+10,116)))
if location['y'] == 0: # 下半边
im_list_down.append(im.crop((abs(location['x']),0,abs(location['x'])+10,58)))
x_offset = 0
for im in im_list_upper:
new_im.paste(im,(x_offset,0)) # 把小图片放到 新的空白图片上
x_offset += im.size[0]
x_offset = 0
for im in im_list_down:
new_im.paste(im,(x_offset,58))
x_offset += im.size[0]
new_im.show()
return new_im
def get_image(driver,div_path):
'''
下载无序的图片 然后进行拼接 获得完整的图片
:param driver:
:param div_path:
:return:
'''
time.sleep(2)
background_images = driver.find_elements_by_xpath(div_path)
location_list = []
for background_image in background_images:
location = {}
result = re.findall('background-image: url\("(.*?)"\); background-position: (.*?)px (.*?)px;',background_image.get_attribute('style'))
# print(result)
location['x'] = int(result[0][1])
location['y'] = int(result[0][2])
image_url = result[0][0]
location_list.append(location)
print('==================================')
image_url = image_url.replace('webp','jpg')
# '替换url http://static.geetest.com/pictures/gt/579066de6/579066de6.webp'
image_result = requests.get(image_url).content
# with open('1.jpg','wb') as f:
# f.write(image_result)
image_file = BytesIO(image_result) # 是一张无序的图片
image = merge_image(image_file,location_list)
return image
按照位移移动8 D% o4 O. O( F' B) }; U$ a
print('第一步,点击滑动按钮')
ActionChains(driver).click_and_hold(on_element=element).perform() # 点击鼠标左键，按住不放
time.sleep(1)
print('第二步,拖动元素')
for track in track_list:
ActionChains(driver).move_by_offset(xoffset=track, yoffset=0).perform() # 鼠标移动到距离当前位置（x,y）
if l<100:
ActionChains(driver).move_by_offset(xoffset=-2, yoffset=0).perform()
else:
ActionChains(driver).move_by_offset(xoffset=-5, yoffset=0).perform()
time.sleep(1)
print('第三步,释放鼠标')
ActionChains(driver).release(on_element=element).perform()
详细代码) R7 R/ O8 }& x+ S+ I& {
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait # 等待元素加载的
from selenium.webdriver.common.action_chains import ActionChains #拖拽
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException, NoSuchElementException
from selenium.webdriver.common.by import By
from PIL import Image
import requests
import time
import re
import random
from io import BytesIO
def merge_image(image_file,location_list):
"""
拼接图片
:param image_file:
:param location_list:
:return:
"""
im = Image.open(image_file)
im.save('code.jpg')
new_im = Image.new('RGB',(260,116))
# 把无序的图片 切成52张小图片
im_list_upper = []
im_list_down = []
# print(location_list)
for location in location_list:
# print(location['y'])
if location['y'] == -58: # 上半边
im_list_upper.append(im.crop((abs(location['x']),58,abs(location['x'])+10,116)))
if location['y'] == 0: # 下半边
im_list_down.append(im.crop((abs(location['x']),0,abs(location['x'])+10,58)))
x_offset = 0
for im in im_list_upper:
new_im.paste(im,(x_offset,0)) # 把小图片放到 新的空白图片上
x_offset += im.size[0]
x_offset = 0
for im in im_list_down:
new_im.paste(im,(x_offset,58))
x_offset += im.size[0]
new_im.show()
return new_im
def get_image(driver,div_path):
'''
下载无序的图片 然后进行拼接 获得完整的图片
:param driver:
:param div_path:
:return:
'''
time.sleep(2)
background_images = driver.find_elements_by_xpath(div_path)
location_list = []
for background_image in background_images:
location = {}
result = re.findall('background-image: url\("(.*?)"\); background-position: (.*?)px (.*?)px;',background_image.get_attribute('style'))
# print(result)
location['x'] = int(result[0][1])
location['y'] = int(result[0][2])
image_url = result[0][0]
location_list.append(location)
print('==================================')
image_url = image_url.replace('webp','jpg')
# '替换url http://static.geetest.com/pictures/gt/579066de6/579066de6.webp'
image_result = requests.get(image_url).content
# with open('1.jpg','wb') as f:
# f.write(image_result)
image_file = BytesIO(image_result) # 是一张无序的图片
image = merge_image(image_file,location_list)
return image
def get_track(distance):
'''
拿到移动轨迹，模仿人的滑动行为，先匀加速后匀减速
匀变速运动基本公式：
①v=v0+at
②s=v0t+(1/2)at²
③v²-v0²=2as
:param distance: 需要移动的距离
:return: 存放每0.2秒移动的距离
'''
# 初速度
v=0
# 单位时间为0.2s来统计轨迹，轨迹即0.2内的位移
t=0.2
# 位移/轨迹列表，列表内的一个元素代表0.2s的位移
tracks=[]
# 当前的位移
current=0
# 到达mid值开始减速
mid=distance * 7/8
distance += 10 # 先滑过一点，最后再反着滑动回来
# a = random.randint(1,3)
while current < distance:
if current < mid:
# 加速度越小，单位时间的位移越小,模拟的轨迹就越多越详细
a = random.randint(2,4) # 加速运动
else:
a = -random.randint(3,5) # 减速运动
# 初速度
v0 = v
# 0.2秒时间内的位移
s = v0*t+0.5*a*(t**2)
# 当前的位置
current += s
# 添加到轨迹列表
tracks.append(round(s))
# 速度已经达到v,该速度作为下次的初速度
v= v0+a*t
# 反着滑动到大概准确位置
for i in range(4):
tracks.append(-random.randint(2,3))
for i in range(4):
tracks.append(-random.randint(1,3))
return tracks
def get_distance(image1,image2):
'''
拿到滑动验证码需要移动的距离
:param image1:没有缺口的图片对象
:param image2:带缺口的图片对象
:return:需要移动的距离
'''
# print('size', image1.size)
threshold = 50
for i in range(0,image1.size[0]): # 260
for j in range(0,image1.size[1]): # 160
pixel1 = image1.getpixel((i,j))
pixel2 = image2.getpixel((i,j))
res_R = abs(pixel1[0]-pixel2[0]) # 计算RGB差
res_G = abs(pixel1[1] - pixel2[1]) # 计算RGB差
res_B = abs(pixel1[2] - pixel2[2]) # 计算RGB差
if res_R > threshold and res_G > threshold and res_B > threshold:
return i # 需要移动的距离
def main_check_code(driver, element):
"""
拖动识别验证码
:param driver:
:param element:
:return:
"""
image1 = get_image(driver, '//div[@class="gt_cut_bg gt_show"]/div')
image2 = get_image(driver, '//div[@class="gt_cut_fullbg gt_show"]/div')
# 图片上 缺口的位置的x坐标
# 2 对比两张图片的所有RBG像素点，得到不一样像素点的x值，即要移动的距离
l = get_distance(image1, image2)
print('l=',l)
# 3 获得移动轨迹
track_list = get_track(l)
print('第一步,点击滑动按钮')
ActionChains(driver).click_and_hold(on_element=element).perform() # 点击鼠标左键，按住不放
time.sleep(1)
print('第二步,拖动元素')
for track in track_list:
ActionChains(driver).move_by_offset(xoffset=track, yoffset=0).perform() # 鼠标移动到距离当前位置（x,y）
time.sleep(0.002)
# if l>100:
ActionChains(driver).move_by_offset(xoffset=-random.randint(2,5), yoffset=0).perform()
time.sleep(1)
print('第三步,释放鼠标')
ActionChains(driver).release(on_element=element).perform()
time.sleep(5)
def main_check_slider(driver):
"""
检查滑动按钮是否加载
:param driver:
:return:
"""
while True:
try :
driver.get('http://www.cnbaowen.net/api/geetest/')
element = WebDriverWait(driver, 30, 0.5).until(EC.element_to_be_clickable((By.CLASS_NAME, 'gt_slider_knob')))
if element:
return element
except TimeoutException as e:
print('超时错误，继续')
time.sleep(5)
if __name__ == '__main__':
try:
count = 6 # 最多识别6次
driver = webdriver.Chrome()
# 等待滑动按钮加载完成
element = main_check_slider(driver)
while count > 0:
main_check_code(driver,element)
time.sleep(2)
try:
success_element = (By.CSS_SELECTOR, '.gt_holder .gt_ajax_tip.gt_success')
# 得到成功标志
print('suc=',driver.find_element_by_css_selector('.gt_holder .gt_ajax_tip.gt_success'))
success_images = WebDriverWait(driver, 20).until(EC.presence_of_element_located(success_element))
if success_images:
print('成功识别！！！！！！')
count = 0
break
except NoSuchElementException as e:
print('识别错误，继续')
count -= 1
time.sleep(2)
else:
print('too many attempt check code ')
exit('退出程序')
finally:
driver.close()
成功识别标志css
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发表于 2019-5-31 10:37:54