1.Array.unshift()
" h( r2 s8 R( u4 Jlet fruits = ["Apple", "Banana", "Mango"];
fruits.unshift("Orange");
console.log(fruits);
// Prints ["Orange", "Apple", "Banana", "Mango"]
fruits.unshift("Guava", "Papaya");
console.log(fruits);
// Prints ["Guava", "Papaya", "Orange", "Apple", "Banana", "Mango"] 2.使用展开运算符(...)
# g5 o' ?4 I* Ivar fruits = ["Apple", "Banana", "Mango"];
var moreFruits = ["Orange", ...fruits];
console.log(moreFruits);
// Prints ["Orange", "Apple", "Banana", "Mango"]
var someoMoreFruits = ["Guava", "Papaya", ...moreFruits];
console.log(someoMoreFruits);
// Prints ["Guava", "Papaya", "Orange", "Apple", "Banana", "Mango"]
console.log(fruits);
// Prints ["Apple", "Banana", "Mango"] 3.使用 Array.concat()
' K- u O) ]# @$ c: J/ y7 ` 我们还可以使用concat()方法在开头连接两个(或更多)数组。
. ]0 \3 y6 v1 k. i& T; }1 Kvar fruits = ["Apple", "Banana", "Mango"];
var moreFruits = ["Orange"];
var someoMoreFruits = ["Guava", "Papaya"];
var allFruits = someoMoreFruits.concat(moreFruits, fruits);
console.log(allFruits);
// Prints ["Guava", "Papaya", "Orange", "Apple", "Banana", "Mango"]
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